In any golden rectangle the following poreperty should hold:
[tex]\frac{a+b}{a}=\frac{a}{b}[/tex]
where a+b is the length and a is the width. We know that the length of the rectangle is 1, then:
[tex]\begin{gathered} a+b=1 \\ b=1-a \end{gathered}[/tex]
Plugging this values in the first equation we have:
[tex]\frac{1}{a}=\frac{a}{1-a}[/tex]
Solving this equation for a:
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