Solution:
Given the circle;
From the circle theorem, triangle PBC is a right triangle.
[tex]\begin{gathered} PB=PD=9 \\ \\ PC=PD+DC=9+32 \\ \\ PC=41 \end{gathered}[/tex]
Using the Pythagorean theorem;
[tex]\begin{gathered} BC=\sqrt{PC^2-PB^2} \\ \\ BC=\sqrt{41^2-9^2} \\ \\ BC=\sqrt{1600} \\ \\ BC=40 \end{gathered}[/tex]
CORRECT OPTION: C
