Since the endpoints of the diameter are (10, 1) and (-8, 1)
Then the center of the circle is the midpoint of these 2 points
We will use the rule of the midpoint to find the center
[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex][tex]\begin{gathered} M=(\frac{10+-8}{2},\frac{1+1}{2}) \\ \\ M=(\frac{2}{2},\frac{2}{2}) \\ \\ M=(1,1) \end{gathered}[/tex]The center of the circle is (1, 1)
The length of the diameter is the difference between the x-coordinate
