Given,
The measure of the hypotenuse is 15 inches.
The measure of the base is 10 inches.
The measure of the perpendicular is x inches.
By Pythagoras theorem,
[tex]\text{hypotenuse}^2=\text{perpendicular}^2+\text{base}^2[/tex]
Substituting the values then,
[tex]\begin{gathered} \text{hypotenuse}^2=\text{perpendicular}^2+\text{base}^2 \\ 15^2=x^2+10^2 \\ 225=x^2+100 \\ 225-100=x^2 \\ x=\sqrt[]{125} \\ x\approx11.18 \end{gathered}[/tex]
