[tex]\bf \qquad \textit{Continuously Compounded Interest Earned Amount}\\\\
A=Pe^{rt}\qquad
\begin{cases}
A=\textit{accumulated amount}\to &\$15000\\
P=\textit{original amount}\\
r=rate\to 5.9\%\to \frac{5.9}{100}\to &0.059\\
t=years\to &12
\end{cases}
\\\\\\
15000=Pe^{0.059\cdot 12}[/tex]
solve for P
