[tex](3x+9x)^{14}=67[/tex] [tex](12x)^{14}=67[/tex] take 14th root of both sides (like cube root but 14th) remember to take positive and negaitve roots [tex]12x=+/-\sqrt[14]{67}[/tex] divide both sides by 12 [tex]x=\frac{+/-\sqrt[14]{67}}{12}[/tex] [tex]x=\frac{sqrt[14]{67}}{12}[/tex] or [tex]x=\frac{-sqrt[14]{67}}{12}[/tex]
