Answer with Step-by-step explanation:
2x-y=4 ⇒y=2x-4
x²+y²=13
⇒ x²+(2x-4)²=13
⇒ x²+4x²+16-16x=13
⇒ 5x²-16x+3=0
⇒ 5x²-15x-x+3=0
5x(x-3)-1(x-3)=0
⇒ (5x-1)(x-3)=0
either 5x-1=0 or x-3=0
x=1/5 or x=3
when x=1/5=0.2, y=2/5-4 i.e. y=-3.6
when x=3, y=2
Hence, solution of x²+y²=13 and 2x-y=4 is:
x=0.2,y= -3.6 and x=3,y=2
