mirandaroxs7736 mirandaroxs7736
  • 03-04-2018
  • Mathematics
contestada

A line passes through points (-4, -19) and (-6, 4). what is the equation of the line written in slope-intercept form?

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demariaa01 demariaa01
  • 03-04-2018
The equation of the line written in slope-intercept form is:

[tex]y = mx + b[/tex]
Where m is the slope and b is the y-intercept.
You find the slope using the formula:

[tex]m = \frac{yb - ya}{xb - xa} [/tex]
Where point A coordinates' are (-4,-19) and point B (-6, 4).

[tex]m = \frac{4 + 19}{ - 6 + 4} [/tex]
[tex]m = - \frac{23}{2} [/tex]
Now you find b (y-intercept) substituting in y=-23/2x+b the coordinates of point A or point B:
(I'll use point B coordinates')
y=-23/2x+b
4=-23/2×(-6)+b
4=46+b
b=-42
The equation of the line is y=-23/2x-42
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