How many moles of potassium hydroxide are needed to complete neutralize 1.50 moles of sulfuric acid (h2so4). please show all work. 2koh + h2so4 -> k2so4 + 2h2o?
The balanced equation for the reaction is 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O
The stoichiometric ratio between KOH and H₂SO₄ is 2 : 1
The moles of Sulfuric acid = 1.5 mol moles of KOH / moles of H₂SO₄= 2 / 1 moles of KOH / 1.5 mol = 2 moles of KOH = 2 x 1.5 mol = 3.0 mol Hence, 3.0 moles of KOH are needed to neutralize the given H₂SO₄ acid
